{"id":4304,"date":"2022-09-12T11:23:22","date_gmt":"2022-09-12T09:23:22","guid":{"rendered":"https:\/\/erlebnisland-mathematik.de\/?page_id=4304"},"modified":"2024-02-22T14:45:42","modified_gmt":"2024-02-22T13:45:42","slug":"advanced-text-how-big-is-the-area-of-a-circle","status":"publish","type":"page","link":"https:\/\/erlebnisland-mathematik.de\/en\/advanced-text-how-big-is-the-area-of-a-circle\/","title":{"rendered":"Advanced text How big is the area of a circle?"},"content":{"rendered":"<div class=\"wpb-content-wrapper\"><p>[vc_row drowwidth=&#8221;sidebar-biest-default sidebar-biest&#8221;][vc_column][vc_column_text]<\/p>\n<h1>How big is the area of a circle?<\/h1>\n<p> This question already preoccupied the Egyptians around 2000 BC. This exhibit should help you find an answer to this question yourself. By &#8220;<em>cleverly<\/em>&#8221; flipping sectors of a given circle, one can see that its area is exactly the same as that of a parallelogram-like figure (cf. Figure 3). In this way, one obtains a relationship between the circumference and the area of a circle.[\/vc_column_text][vc_column_text]<\/p>\n<h3>And now &#8230; the mathematics:<\/h3>\n<p>[\/vc_column_text][vc_column_text]First, you decompose the given circle into <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> congruent <em>circle sectors<\/em>. Here <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> should be even (for odd <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> an analogous procedure, but with a <em>&#8220;<\/em><em>trapezoid&#8221;<\/em> instead of a <em>&#8220;parallelogram&#8221;<\/em>, would lead to the same result). In our example <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-e63fb3a6904e053b0f30673092809f8d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;&#61;&#49;&#50;\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"49\" style=\"vertical-align: 0px;\"\/> was chosen.[\/vc_column_text][vc_single_image image=&#8221;1216&#8243; img_size=&#8221;large&#8221; alignment=&#8221;center&#8221;]Figure 1: The circle divided into twelve sectors[\/vc_single_image][vc_column_text]Each of these sectors has the following shape:[\/vc_column_text][vc_single_image image=&#8221;1220&#8243; img_size=&#8221;large&#8221; alignment=&#8221;center&#8221;]Figure 2: A circle sector[\/vc_single_image][vc_column_text]Anyone who takes a closer look at the exhibit quickly realises that simple &#8220;<em>trial and error<\/em>&#8221; or even &#8220;<em>brute force<\/em>&#8221; will not get you anywhere with the task of determining the area of the circle, at least approximately. But there is a good approximate solution. This looks like this:[\/vc_column_text][vc_single_image image=&#8221;1224&#8243; img_size=&#8221;large&#8221; alignment=&#8221;center&#8221;]Figure 3: The solution offered by the exhibit[\/vc_single_image][vc_column_text]One now looks for correlations between the underlying circle and the associated &#8220;<em>parallelogram<\/em>&#8221; (Figure 3). It applies:<\/p>\n<ul>\n<li>The circle and the &#8220;<em>parallelogram<\/em>&#8221; have the same area.<\/li>\n<li>As <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> increases, the &#8220;<em>parallelogram<\/em>&#8221; becomes more and more like a rectangle whose height is the <em>radius<\/em> <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-94672b7526308efaca1985a5ecdae780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"7\" style=\"vertical-align: 0px;\"\/> of the given circle and whose width is equal to half the circumference <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-c066466cd45c28a891e81cca78484d27_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#112;&#47;&#50;\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"27\" style=\"vertical-align: -5px;\"\/> of the same.<\/li>\n<\/ul>\n<p>Why? The reason(s):<\/p>\n<ul>\n<li>Since the circle and the &#8220;<em>parallelogram<\/em>&#8221; are composed of the same parts, both must have the same area. Expressed mathematically: <em>equality of decomposition<\/em> implies <em>equality of content<\/em>.<\/li>\n<li>The sectors of the circle of the same size come closer and closer to a distance of length <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-94672b7526308efaca1985a5ecdae780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"7\" style=\"vertical-align: 0px;\"\/> as <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> grows. In the &#8220;<em>parallelogram<\/em>&#8221; they stand &#8220;<em>upright<\/em>&#8220;. Therefore, its height approaches more and more the radius <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-94672b7526308efaca1985a5ecdae780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"7\" style=\"vertical-align: 0px;\"\/> (cf. Figure 3).<\/li>\n<li>If the sectors lie in the circle (cf. Figure 1), the circumference <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-fc8c8e0f072953d1bf5f36c0dd8227a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#112;\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"10\" style=\"vertical-align: -4px;\"\/> of the circle corresponds to the product <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-58d2ae5ae6116311b9ea4b9ec5b2c1f1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;&#92;&#99;&#100;&#111;&#116;&#32;&#98;\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"31\" style=\"vertical-align: 0px;\"\/> of the number <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8ad02d5f0d297c7adacb6b8c4f9fee74_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"\/> of sectors (in our example <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-e63fb3a6904e053b0f30673092809f8d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;&#61;&#49;&#50;\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"49\" style=\"vertical-align: 0px;\"\/>) with the arc length <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-522dc16829b6bc97d06ce10c3e5dabb7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#98;\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"9\" style=\"vertical-align: 0px;\"\/> of a sector (cf. Figure 2). In the &#8220;<em>parallelogram<\/em>&#8221; (figure 3), exactly half of the sectors are positioned so that their tip points upwards and the other half in the opposite direction. This arrangement results in the length of the base side of the &#8220;<em>parallelogram<\/em>&#8221; approaching more and more the value <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-ef595f74143d2a2d668376bb2ffe5192_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#92;&#102;&#114;&#97;&#99;&#123;&#110;&#125;&#123;&#50;&#125;&#92;&#99;&#100;&#111;&#116;&#32;&#98;&#61;&#112;&#47;&#50;\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"82\" style=\"vertical-align: -6px;\"\/>.<\/li>\n<\/ul>\n<p>Summarising these considerations, we get for the area <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-f0dda122e6dd726b68ff7f83ecb0ffd1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#65;\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"12\" style=\"vertical-align: 0px;\"\/> of the parallelogram (which is equal to the area of the circle): <\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 32px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-672b7579f86537d9039db192737513a8_l3.png\" height=\"32\" width=\"129\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91;&#65;&#61;&#97;&#92;&#99;&#100;&#111;&#116;&#32;&#104;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#125;&#123;&#50;&#125;&#92;&#99;&#100;&#111;&#116;&#32;&#114;&#44;&#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>because &#8212; as justified above &#8212; for <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-611d05decdb0205142fb7562c2401d8c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#110;&#92;&#116;&#111;&#92;&#105;&#110;&#102;&#116;&#121;\" title=\"Rendered by QuickLaTeX.com\" height=\"10\" width=\"53\" style=\"vertical-align: -1px;\"\/> it approaches more and more a rectangle of height <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-e91539ec189f085995fa28042aab0547_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#104;&#61;&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"40\" style=\"vertical-align: 0px;\"\/> and base side of length <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-8effd794f6e4a7bb8576c71c31255cfa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#97;&#61;&#112;&#47;&#50;\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"58\" style=\"vertical-align: -5px;\"\/>. From this follows the formula for the circular area: <\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 32px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-4e5e0ea87d14516b2b2afe653ce5bb5a_l3.png\" height=\"32\" width=\"60\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91;&#65;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#32;&#114;&#125;&#32;&#123;&#50;&#125;&#32;&#46;&#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>This result can now be brought together with the one from the exhibit <a href=\"https:\/\/erlebnisland-mathematik.de\/en\/?post_type=exponat&amp;p=3530\"><em>&#8220;What is Pi?&#8221;<\/em><\/a>. There one learns that <\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 32px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-e55aedcaf0f9832d63fe406d96058435_l3.png\" height=\"32\" width=\"97\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91;&#92;&#112;&#105;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#125;&#123;&#100;&#125;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#125;&#123;&#50;&#114;&#125;&#46;&#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>Here <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-82199a57cf64b9df9f759d4a440cc85c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#100;&#61;&#50;&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"50\" style=\"vertical-align: 0px;\"\/> is the <em>diameter<\/em> of the given circle. Altogether, the area of the circle of radius <img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-94672b7526308efaca1985a5ecdae780_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"&#114;\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"7\" style=\"vertical-align: 0px;\"\/> is: <\/p>\n<p class=\"ql-center-displayed-equation\" style=\"line-height: 32px;\"><span class=\"ql-right-eqno\"> &nbsp; <\/span><span class=\"ql-left-eqno\"> &nbsp; <\/span><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/erlebnisland-mathematik.de\/wp-content\/ql-cache\/quicklatex.com-3795e639bb1ed9eab317ac4087368498_l3.png\" height=\"32\" width=\"183\" class=\"ql-img-displayed-equation quicklatex-auto-format\" alt=\"&#92;&#91;&#65;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#32;&#114;&#125;&#32;&#123;&#50;&#125;&#32;&#61;&#92;&#102;&#114;&#97;&#99;&#123;&#112;&#125;&#123;&#50;&#114;&#125;&#92;&#99;&#100;&#111;&#116;&#32;&#114;&#94;&#50;&#61;&#92;&#112;&#105;&#32;&#114;&#94;&#50;&#44;&#92;&#93;\" title=\"Rendered by QuickLaTeX.com\"\/><\/p>\n<p>which corresponds to the known formula for the circular area.[\/vc_column_text][\/vc_column][\/vc_row]<\/p>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>[vc_row drowwidth=&#8221;sidebar-biest-default sidebar-biest&#8221;][vc_column][vc_column_text] How big is the area of a circle? This question already preoccupied the Egyptians around 2000 BC. This exhibit should help you find an answer to this question yourself. By &#8220;cleverly&#8221; flipping sectors of a given circle, one can see that its area is exactly the same as that of a parallelogram-like <a href=\"https:\/\/erlebnisland-mathematik.de\/en\/advanced-text-how-big-is-the-area-of-a-circle\/\" class=\"more-link\">&#8230;<span class=\"screen-reader-text\">  Advanced text How big is the area of a circle?<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"_acf_changed":false,"footnotes":""},"folder":[],"class_list":["post-4304","page","type-page","status-publish","hentry"],"acf":[],"_links":{"self":[{"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/pages\/4304","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/comments?post=4304"}],"version-history":[{"count":7,"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/pages\/4304\/revisions"}],"predecessor-version":[{"id":5382,"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/pages\/4304\/revisions\/5382"}],"wp:attachment":[{"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/media?parent=4304"}],"wp:term":[{"taxonomy":"folder","embeddable":true,"href":"https:\/\/erlebnisland-mathematik.de\/en\/wp-json\/wp\/v2\/folder?post=4304"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}